2x+2(4x-2)+3x=x+3(x-8)+4x

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Solution for 2x+2(4x-2)+3x=x+3(x-8)+4x equation: 



2x+2(4x-2)+3x=x+3(x-8)+4x

We move all terms to the left:

2x+2(4x-2)+3x-(x+3(x-8)+4x)=0

We add all the numbers together, and all the variables

5x+2(4x-2)-(x+3(x-8)+4x)=0

We multiply parentheses

5x+8x-(x+3(x-8)+4x)-4=0



We calculate terms in parentheses: -(x+3(x-8)+4x), so:

x+3(x-8)+4x

We add all the numbers together, and all the variables

5x+3(x-8)

We multiply parentheses

5x+3x-24

We add all the numbers together, and all the variables

8x-24

Back to the equation:

-(8x-24)



We add all the numbers together, and all the variables

13x-(8x-24)-4=0

We get rid of parentheses

13x-8x+24-4=0

We add all the numbers together, and all the variables

5x+20=0

We move all terms containing x to the left, all other terms to the right

5x=-20

x=-20/5

x=-4

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