2x+2(x+3)=10+2(x+1)+2

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Solution for 2x+2(x+3)=10+2(x+1)+2 equation:



2x+2(x+3)=10+2(x+1)+2
We move all terms to the left:
2x+2(x+3)-(10+2(x+1)+2)=0
We multiply parentheses
2x+2x-(10+2(x+1)+2)+6=0
We calculate terms in parentheses: -(10+2(x+1)+2), so:
10+2(x+1)+2
determiningTheFunctionDomain 2(x+1)+10+2
We add all the numbers together, and all the variables
2(x+1)+12
We multiply parentheses
2x+2+12
We add all the numbers together, and all the variables
2x+14
Back to the equation:
-(2x+14)
We add all the numbers together, and all the variables
4x-(2x+14)+6=0
We get rid of parentheses
4x-2x-14+6=0
We add all the numbers together, and all the variables
2x-8=0
We move all terms containing x to the left, all other terms to the right
2x=8
x=8/2
x=4

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