2x+2(x-4)=68

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Solution for 2x+2(x-4)=68 equation: 



2x+2(x-4)=68

We move all terms to the left:

2x+2(x-4)-(68)=0

We multiply parentheses

2x+2x-8-68=0

We add all the numbers together, and all the variables

4x-76=0

We move all terms containing x to the left, all other terms to the right

4x=76

x=76/4

x=19

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