2x+2(x-7)=(x+9)+(x-7)+(x+2)

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Solution for 2x+2(x-7)=(x+9)+(x-7)+(x+2) equation: 



2x+2(x-7)=(x+9)+(x-7)+(x+2)

We move all terms to the left:

2x+2(x-7)-((x+9)+(x-7)+(x+2))=0

We multiply parentheses

2x+2x-((x+9)+(x-7)+(x+2))-14=0



We calculate terms in parentheses: -((x+9)+(x-7)+(x+2)), so:

(x+9)+(x-7)+(x+2)

We get rid of parentheses

x+x+x+9-7+2

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

4x-(3x+4)-14=0

We get rid of parentheses

4x-3x-4-14=0

We add all the numbers together, and all the variables

x-18=0

We move all terms containing x to the left, all other terms to the right

x=18

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