2x+2(x-8)=8x-6(x-10)

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Solution for 2x+2(x-8)=8x-6(x-10) equation: 



2x+2(x-8)=8x-6(x-10)

We move all terms to the left:

2x+2(x-8)-(8x-6(x-10))=0

We multiply parentheses

2x+2x-(8x-6(x-10))-16=0



We calculate terms in parentheses: -(8x-6(x-10)), so:

8x-6(x-10)

We multiply parentheses

8x-6x+60

We add all the numbers together, and all the variables

2x+60

Back to the equation:

-(2x+60)



We add all the numbers together, and all the variables

4x-(2x+60)-16=0

We get rid of parentheses

4x-2x-60-16=0

We add all the numbers together, and all the variables

2x-76=0

We move all terms containing x to the left, all other terms to the right

2x=76

x=76/2

x=38

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