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2x+2+(-2)+4x=12
We move all terms to the left:
2x+2+(-2)+4x-(12)=0
determiningTheFunctionDomain 2x+4x+2-12+(-2)=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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