2x+2+3x=3(x-2)

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Solution for 2x+2+3x=3(x-2) equation:



2x+2+3x=3(x-2)
We move all terms to the left:
2x+2+3x-(3(x-2))=0
We add all the numbers together, and all the variables
5x-(3(x-2))+2=0
We calculate terms in parentheses: -(3(x-2)), so:
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
We get rid of parentheses
5x-3x+6+2=0
We add all the numbers together, and all the variables
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4

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