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2x+2-3x=4-2(x+1)
We move all terms to the left:
2x+2-3x-(4-2(x+1))=0
We add all the numbers together, and all the variables
-1x-(4-2(x+1))+2=0
We calculate terms in parentheses: -(4-2(x+1)), so:We get rid of parentheses
4-2(x+1)
determiningTheFunctionDomain -2(x+1)+4
We multiply parentheses
-2x-2+4
We add all the numbers together, and all the variables
-2x+2
Back to the equation:
-(-2x+2)
-1x+2x-2+2=0
We add all the numbers together, and all the variables
x=0
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