2x+2/3+x=5(x-1)/4+4

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Solution for 2x+2/3+x=5(x-1)/4+4 equation: 



2x+2/3+x=5(x-1)/4+4

We move all terms to the left:

2x+2/3+x-(5(x-1)/4+4)=0

We add all the numbers together, and all the variables

3x-(5(x-1)/4+4)+2/3=0

We calculate fractions


3x+(-(5(x-1)*3)/()+()/()=0



We calculate terms in parentheses: +(-(5(x-1)*3)/()+()/(), so:

-(5(x-1)*3)/()+()/(

We add all the numbers together, and all the variables

-(5(x-1)*3)/()+1

We multiply all the terms by the denominator


-(5(x-1)*3)+1*()



We calculate terms in parentheses: -(5(x-1)*3), so:

5(x-1)*3

We multiply parentheses

15x-15

Back to the equation:

-(15x-15)



We add all the numbers together, and all the variables

-(15x-15)

We get rid of parentheses

-15x+15

Back to the equation:

+(-15x+15)



We get rid of parentheses

3x-15x+15=0

We add all the numbers together, and all the variables

-12x+15=0

We move all terms containing x to the left, all other terms to the right

-12x=-15

x=-15/-12

x=1+1/4

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