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2x+2/3x=195
We move all terms to the left:
2x+2/3x-(195)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
2x*3x-195*3x+2=0
Wy multiply elements
6x^2-585x+2=0
a = 6; b = -585; c = +2;
Δ = b2-4ac
Δ = -5852-4·6·2
Δ = 342177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-585)-\sqrt{342177}}{2*6}=\frac{585-\sqrt{342177}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-585)+\sqrt{342177}}{2*6}=\frac{585+\sqrt{342177}}{12} $
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