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2x+2/5x+x=102.000
We move all terms to the left:
2x+2/5x+x-(102.000)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2x+2/5x+x-102=0
We add all the numbers together, and all the variables
3x+2/5x-102=0
We multiply all the terms by the denominator
3x*5x-102*5x+2=0
Wy multiply elements
15x^2-510x+2=0
a = 15; b = -510; c = +2;
Δ = b2-4ac
Δ = -5102-4·15·2
Δ = 259980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{259980}=\sqrt{4*64995}=\sqrt{4}*\sqrt{64995}=2\sqrt{64995}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-510)-2\sqrt{64995}}{2*15}=\frac{510-2\sqrt{64995}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-510)+2\sqrt{64995}}{2*15}=\frac{510+2\sqrt{64995}}{30} $
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