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2x+2/x=8
We move all terms to the left:
2x+2/x-(8)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
2x*x-8*x+2=0
We add all the numbers together, and all the variables
-8x+2x*x+2=0
Wy multiply elements
2x^2-8x+2=0
a = 2; b = -8; c = +2;
Δ = b2-4ac
Δ = -82-4·2·2
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{3}}{2*2}=\frac{8-4\sqrt{3}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{3}}{2*2}=\frac{8+4\sqrt{3}}{4} $
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