2x+20-32=2(x-6)

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Solution for 2x+20-32=2(x-6) equation: 



2x+20-32=2(x-6)

We move all terms to the left:

2x+20-32-(2(x-6))=0

We add all the numbers together, and all the variables

2x-(2(x-6))-12=0



We calculate terms in parentheses: -(2(x-6)), so:

2(x-6)

We multiply parentheses

2x-12

Back to the equation:

-(2x-12)



We get rid of parentheses

2x-2x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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