2x+20-5x=3(x-5)

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Solution for 2x+20-5x=3(x-5) equation: 



2x+20-5x=3(x-5)

We move all terms to the left:

2x+20-5x-(3(x-5))=0

We add all the numbers together, and all the variables

-3x-(3(x-5))+20=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We get rid of parentheses

-3x-3x+15+20=0

We add all the numbers together, and all the variables

-6x+35=0

We move all terms containing x to the left, all other terms to the right

-6x=-35

x=-35/-6

x=5+5/6

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