2x+20=(4/3)x

Solution for 2x+20=(4/3)x equation:

2x+20=(4/3)x

We move all terms to the left:

2x+20-((4/3)x)=0


Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-((+4/3)x)+20=0

We multiply all the terms by the denominator


2x*3)x)-((+20*3)x)+4=0

We add all the numbers together, and all the variables

2x*3)x)-(60x)+4=0

We add all the numbers together, and all the variables

2x*3)x)-60x+4=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$