2x+20=(4/7x)

Solution for 2x+20=(4/7x) equation:

2x+20=(4/7x)

We move all terms to the left:

2x+20-((4/7x))=0


Domain of the equation: 7x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-((+4/7x))+20=0

We multiply all the terms by the denominator


2x*7x))-((+20*7x))+4=0

Wy multiply elements

14x^2+140x=0

a = 14; b = 140; c = 0;
Δ = b2-4ac
Δ = 1402-4·14·0
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-140}{2*14}=\frac{-280}{28}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+140}{2*14}=\frac{0}{28}
=0
$