2x+20=3(3x+4)-6

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Solution for 2x+20=3(3x+4)-6 equation: 



2x+20=3(3x+4)-6

We move all terms to the left:

2x+20-(3(3x+4)-6)=0



We calculate terms in parentheses: -(3(3x+4)-6), so:

3(3x+4)-6

We multiply parentheses

9x+12-6

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We get rid of parentheses

2x-9x-6+20=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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