2x+20=3/7x

Solution for 2x+20=3/7x equation:

2x+20=3/7x

We move all terms to the left:

2x+20-(3/7x)=0


Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(+3/7x)+20=0

We get rid of parentheses

2x-3/7x+20=0

We multiply all the terms by the denominator


2x*7x+20*7x-3=0

Wy multiply elements

14x^2+140x-3=0

a = 14; b = 140; c = -3;
Δ = b2-4ac
Δ = 1402-4·14·(-3)
Δ = 19768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19768}=\sqrt{4*4942}=\sqrt{4}*\sqrt{4942}=2\sqrt{4942}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-2\sqrt{4942}}{2*14}=\frac{-140-2\sqrt{4942}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+2\sqrt{4942}}{2*14}=\frac{-140+2\sqrt{4942}}{28}
$