2x+20=4(4x-4)+8

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Solution for 2x+20=4(4x-4)+8 equation: 



2x+20=4(4x-4)+8

We move all terms to the left:

2x+20-(4(4x-4)+8)=0



We calculate terms in parentheses: -(4(4x-4)+8), so:

4(4x-4)+8

We multiply parentheses

16x-16+8

We add all the numbers together, and all the variables

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

2x-16x+8+20=0

We add all the numbers together, and all the variables

-14x+28=0

We move all terms containing x to the left, all other terms to the right

-14x=-28

x=-28/-14

x=+2

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