2x+20=4/3x

Solution for 2x+20=4/3x equation:

2x+20=4/3x

We move all terms to the left:

2x+20-(4/3x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(+4/3x)+20=0

We get rid of parentheses

2x-4/3x+20=0

We multiply all the terms by the denominator


2x*3x+20*3x-4=0

Wy multiply elements

6x^2+60x-4=0

a = 6; b = 60; c = -4;
Δ = b2-4ac
Δ = 602-4·6·(-4)
Δ = 3696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3696}=\sqrt{16*231}=\sqrt{16}*\sqrt{231}=4\sqrt{231}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{231}}{2*6}=\frac{-60-4\sqrt{231}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{231}}{2*6}=\frac{-60+4\sqrt{231}}{12}
$