2x+22=2+5(4-3x)

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Solution for 2x+22=2+5(4-3x) equation: 



2x+22=2+5(4-3x)

We move all terms to the left:

2x+22-(2+5(4-3x))=0

We add all the numbers together, and all the variables

2x-(2+5(-3x+4))+22=0



We calculate terms in parentheses: -(2+5(-3x+4)), so:

2+5(-3x+4)

determiningTheFunctionDomain
5(-3x+4)+2

We multiply parentheses

-15x+20+2

We add all the numbers together, and all the variables

-15x+22

Back to the equation:

-(-15x+22)



We get rid of parentheses

2x+15x-22+22=0

We add all the numbers together, and all the variables

17x=0

x=0/17

x=0

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