2x+22=4(x+4)

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Solution for 2x+22=4(x+4) equation: 



2x+22=4(x+4)

We move all terms to the left:

2x+22-(4(x+4))=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

2x-4x-16+22=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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