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2x+24=300+1/2x
We move all terms to the left:
2x+24-(300+1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(1/2x+300)+24=0
We get rid of parentheses
2x-1/2x-300+24=0
We multiply all the terms by the denominator
2x*2x-300*2x+24*2x-1=0
Wy multiply elements
4x^2-600x+48x-1=0
We add all the numbers together, and all the variables
4x^2-552x-1=0
a = 4; b = -552; c = -1;
Δ = b2-4ac
Δ = -5522-4·4·(-1)
Δ = 304720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304720}=\sqrt{16*19045}=\sqrt{16}*\sqrt{19045}=4\sqrt{19045}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-552)-4\sqrt{19045}}{2*4}=\frac{552-4\sqrt{19045}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-552)+4\sqrt{19045}}{2*4}=\frac{552+4\sqrt{19045}}{8} $
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