2x+2=(4x-4)/8

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Solution for 2x+2=(4x-4)/8 equation: 



2x+2=(4x-4)/8

We move all terms to the left:

2x+2-((4x-4)/8)=0

We multiply all the terms by the denominator


2x*8)-((4x-4)+2*8)=0

We add all the numbers together, and all the variables

2x*8)-((4x-4)=0

Wy multiply elements

16x^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$

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