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2x+2=2(4x+2)-2-6x
We move all terms to the left:
2x+2-(2(4x+2)-2-6x)=0
We calculate terms in parentheses: -(2(4x+2)-2-6x), so:We get rid of parentheses
2(4x+2)-2-6x
determiningTheFunctionDomain 2(4x+2)-6x-2
We add all the numbers together, and all the variables
-6x+2(4x+2)-2
We multiply parentheses
-6x+8x+4-2
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
2x-2x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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