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2x+2=2(x-3)
We move all terms to the left:
2x+2-(2(x-3))=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
2x-2x+6+2=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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