2x+2=3(2x-2)

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Solution for 2x+2=3(2x-2) equation: 



2x+2=3(2x-2)

We move all terms to the left:

2x+2-(3(2x-2))=0



We calculate terms in parentheses: -(3(2x-2)), so:

3(2x-2)

We multiply parentheses

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

2x-6x+6+2=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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