2x+2=x+2-3(x-8/3)

Solution for 2x+2=x+2-3(x-8/3) equation:

2x+2=x+2-3(x-8/3)

We move all terms to the left:

2x+2-(x+2-3(x-8/3))=0

We add all the numbers together, and all the variables

2x-(x+2-3(+x-8/3))+2=0

We multiply all the terms by the denominator


2x*3))-(x+2-3(+x-8+2*3))=0

We add all the numbers together, and all the variables

2x*3))-(x+2-3(x-2))=0

We add all the numbers together, and all the variables

2x*3))-(x+2-3(x=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$