2x+2x(x-1)=4(x-3)+10

Solution for 2x+2x(x-1)=4(x-3)+10 equation:

2x+2x(x-1)=4(x-3)+10

We move all terms to the left:

2x+2x(x-1)-(4(x-3)+10)=0

We multiply parentheses

2x^2+2x-2x-(4(x-3)+10)=0


We calculate terms in parentheses: -(4(x-3)+10), so:

4(x-3)+10

We multiply parentheses

4x-12+10

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)


We add all the numbers together, and all the variables

2x^2-(4x-2)=0

We get rid of parentheses

2x^2-4x+2=0

a = 2; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{4}=1$