2x+2x+(x-8)=4(x+2)

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Solution for 2x+2x+(x-8)=4(x+2) equation: 



2x+2x+(x-8)=4(x+2)

We move all terms to the left:

2x+2x+(x-8)-(4(x+2))=0

We add all the numbers together, and all the variables

4x+(x-8)-(4(x+2))=0

We get rid of parentheses

4x+x-(4(x+2))-8=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

5x-(4x+8)-8=0

We get rid of parentheses

5x-4x-8-8=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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