2x+2x+x-8=4(x-2)

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Solution for 2x+2x+x-8=4(x-2) equation: 



2x+2x+x-8=4(x-2)

We move all terms to the left:

2x+2x+x-8-(4(x-2))=0

We add all the numbers together, and all the variables

5x-(4(x-2))-8=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

5x-4x+8-8=0

We add all the numbers together, and all the variables

x=0

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