2x+3(2x+1)=8(x+1)-5

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Solution for 2x+3(2x+1)=8(x+1)-5 equation: 



2x+3(2x+1)=8(x+1)-5

We move all terms to the left:

2x+3(2x+1)-(8(x+1)-5)=0

We multiply parentheses

2x+6x-(8(x+1)-5)+3=0



We calculate terms in parentheses: -(8(x+1)-5), so:

8(x+1)-5

We multiply parentheses

8x+8-5

We add all the numbers together, and all the variables

8x+3

Back to the equation:

-(8x+3)



We add all the numbers together, and all the variables

8x-(8x+3)+3=0

We get rid of parentheses

8x-8x-3+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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