2x+3(2x-1)+1=1/2(8x-12)

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Solution for 2x+3(2x-1)+1=1/2(8x-12) equation: 



2x+3(2x-1)+1=1/2(8x-12)

We move all terms to the left:

2x+3(2x-1)+1-(1/2(8x-12))=0



Domain of the equation: 2(8x-12))!=0

x∈R



We multiply parentheses

2x+6x-(1/2(8x-12))-3+1=0

We multiply all the terms by the denominator


2x*2(8x-12))+6x*2(8x-12))-(1-3*2(8x-12))+1*2(8x-12))=0

Wy multiply elements

8x^3(8-12))-(1-3*2(8x-12))+1*2(8x-12))=0

We do not support expression: x^3(8

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