2x+3(3+2x)=2(3x-2)

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Solution for 2x+3(3+2x)=2(3x-2) equation: 



2x+3(3+2x)=2(3x-2)

We move all terms to the left:

2x+3(3+2x)-(2(3x-2))=0

We add all the numbers together, and all the variables

2x+3(2x+3)-(2(3x-2))=0

We multiply parentheses

2x+6x-(2(3x-2))+9=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

8x-(6x-4)+9=0

We get rid of parentheses

8x-6x+4+9=0

We add all the numbers together, and all the variables

2x+13=0

We move all terms containing x to the left, all other terms to the right

2x=-13

x=-13/2

x=-6+1/2

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