2x+3(3x+1)=9x-19

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Solution for 2x+3(3x+1)=9x-19 equation: 



2x+3(3x+1)=9x-19

We move all terms to the left:

2x+3(3x+1)-(9x-19)=0

We multiply parentheses

2x+9x-(9x-19)+3=0

We get rid of parentheses

2x+9x-9x+19+3=0

We add all the numbers together, and all the variables

2x+22=0

We move all terms containing x to the left, all other terms to the right

2x=-22

x=-22/2

x=-11

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