2x+3(3x+1)=9x-19

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Solution for 2x+3(3x+1)=9x-19 equation:



2x+3(3x+1)=9x-19
We move all terms to the left:
2x+3(3x+1)-(9x-19)=0
We multiply parentheses
2x+9x-(9x-19)+3=0
We get rid of parentheses
2x+9x-9x+19+3=0
We add all the numbers together, and all the variables
2x+22=0
We move all terms containing x to the left, all other terms to the right
2x=-22
x=-22/2
x=-11

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