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2x+3(3x+15)=76
We move all terms to the left:
2x+3(3x+15)-(76)=0
We multiply parentheses
2x+9x+45-76=0
We add all the numbers together, and all the variables
11x-31=0
We move all terms containing x to the left, all other terms to the right
11x=31
x=31/11
x=2+9/11
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