2x+3(3x-2)=104

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Solution for 2x+3(3x-2)=104 equation: 



2x+3(3x-2)=104

We move all terms to the left:

2x+3(3x-2)-(104)=0

We multiply parentheses

2x+9x-6-104=0

We add all the numbers together, and all the variables

11x-110=0

We move all terms containing x to the left, all other terms to the right

11x=110

x=110/11

x=10

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