2x+3(3x-2)=8-2(5+3x)

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Solution for 2x+3(3x-2)=8-2(5+3x) equation: 



2x+3(3x-2)=8-2(5+3x)

We move all terms to the left:

2x+3(3x-2)-(8-2(5+3x))=0

We add all the numbers together, and all the variables

2x+3(3x-2)-(8-2(3x+5))=0

We multiply parentheses

2x+9x-(8-2(3x+5))-6=0



We calculate terms in parentheses: -(8-2(3x+5)), so:

8-2(3x+5)

determiningTheFunctionDomain
-2(3x+5)+8

We multiply parentheses

-6x-10+8

We add all the numbers together, and all the variables

-6x-2

Back to the equation:

-(-6x-2)



We add all the numbers together, and all the variables

11x-(-6x-2)-6=0

We get rid of parentheses

11x+6x+2-6=0

We add all the numbers together, and all the variables

17x-4=0

We move all terms containing x to the left, all other terms to the right

17x=4

x=4/17

x=4/17

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