2x+3(4+x)=48

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Solution for 2x+3(4+x)=48 equation: 



2x+3(4+x)=48

We move all terms to the left:

2x+3(4+x)-(48)=0

We add all the numbers together, and all the variables

2x+3(x+4)-48=0

We multiply parentheses

2x+3x+12-48=0

We add all the numbers together, and all the variables

5x-36=0

We move all terms containing x to the left, all other terms to the right

5x=36

x=36/5

x=7+1/5

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