2x+3(4x-5)=4x+65

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Solution for 2x+3(4x-5)=4x+65 equation: 



2x+3(4x-5)=4x+65

We move all terms to the left:

2x+3(4x-5)-(4x+65)=0

We multiply parentheses

2x+12x-(4x+65)-15=0

We get rid of parentheses

2x+12x-4x-65-15=0

We add all the numbers together, and all the variables

10x-80=0

We move all terms containing x to the left, all other terms to the right

10x=80

x=80/10

x=8

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