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2x+3(4x-6)=3(x+4)+x
We move all terms to the left:
2x+3(4x-6)-(3(x+4)+x)=0
We multiply parentheses
2x+12x-(3(x+4)+x)-18=0
We calculate terms in parentheses: -(3(x+4)+x), so:We add all the numbers together, and all the variables
3(x+4)+x
We add all the numbers together, and all the variables
x+3(x+4)
We multiply parentheses
x+3x+12
We add all the numbers together, and all the variables
4x+12
Back to the equation:
-(4x+12)
14x-(4x+12)-18=0
We get rid of parentheses
14x-4x-12-18=0
We add all the numbers together, and all the variables
10x-30=0
We move all terms containing x to the left, all other terms to the right
10x=30
x=30/10
x=3
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