2x+3(x+1)=2(3x+1)-4

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Solution for 2x+3(x+1)=2(3x+1)-4 equation: 



2x+3(x+1)=2(3x+1)-4

We move all terms to the left:

2x+3(x+1)-(2(3x+1)-4)=0

We multiply parentheses

2x+3x-(2(3x+1)-4)+3=0



We calculate terms in parentheses: -(2(3x+1)-4), so:

2(3x+1)-4

We multiply parentheses

6x+2-4

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

5x-(6x-2)+3=0

We get rid of parentheses

5x-6x+2+3=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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