2x+3(x+12)+6(.5x)=100

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Solution for 2x+3(x+12)+6(.5x)=100 equation: 



2x+3(x+12)+6(.5x)=100

We move all terms to the left:

2x+3(x+12)+6(.5x)-(100)=0

We add all the numbers together, and all the variables

2x+3(x+12)+6(+.5x)-100=0

We multiply parentheses

2x+3x+6x+36-100=0

We add all the numbers together, and all the variables

11x-64=0

We move all terms containing x to the left, all other terms to the right

11x=64

x=64/11

x=5+9/11

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