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2x+3(x+2)=5(x-4)
We move all terms to the left:
2x+3(x+2)-(5(x-4))=0
We multiply parentheses
2x+3x-(5(x-4))+6=0
We calculate terms in parentheses: -(5(x-4)), so:We add all the numbers together, and all the variables
5(x-4)
We multiply parentheses
5x-20
Back to the equation:
-(5x-20)
5x-(5x-20)+6=0
We get rid of parentheses
5x-5x+20+6=0
We add all the numbers together, and all the variables
26!=0
There is no solution for this equation
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