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2x+3(x+4)=5(x+3)
We move all terms to the left:
2x+3(x+4)-(5(x+3))=0
We multiply parentheses
2x+3x-(5(x+3))+12=0
We calculate terms in parentheses: -(5(x+3)), so:We add all the numbers together, and all the variables
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
5x-(5x+15)+12=0
We get rid of parentheses
5x-5x-15+12=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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