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2x+3(x-1)=4-3(2x-5)
We move all terms to the left:
2x+3(x-1)-(4-3(2x-5))=0
We multiply parentheses
2x+3x-(4-3(2x-5))-3=0
We calculate terms in parentheses: -(4-3(2x-5)), so:We add all the numbers together, and all the variables
4-3(2x-5)
determiningTheFunctionDomain -3(2x-5)+4
We multiply parentheses
-6x+15+4
We add all the numbers together, and all the variables
-6x+19
Back to the equation:
-(-6x+19)
5x-(-6x+19)-3=0
We get rid of parentheses
5x+6x-19-3=0
We add all the numbers together, and all the variables
11x-22=0
We move all terms containing x to the left, all other terms to the right
11x=22
x=22/11
x=2
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