2x+3(x-2)=4(1-5x)-8

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Solution for 2x+3(x-2)=4(1-5x)-8 equation: 



2x+3(x-2)=4(1-5x)-8

We move all terms to the left:

2x+3(x-2)-(4(1-5x)-8)=0

We add all the numbers together, and all the variables

2x+3(x-2)-(4(-5x+1)-8)=0

We multiply parentheses

2x+3x-(4(-5x+1)-8)-6=0



We calculate terms in parentheses: -(4(-5x+1)-8), so:

4(-5x+1)-8

We multiply parentheses

-20x+4-8

We add all the numbers together, and all the variables

-20x-4

Back to the equation:

-(-20x-4)



We add all the numbers together, and all the variables

5x-(-20x-4)-6=0

We get rid of parentheses

5x+20x+4-6=0

We add all the numbers together, and all the variables

25x-2=0

We move all terms containing x to the left, all other terms to the right

25x=2

x=2/25

x=2/25

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