2x+3(x-3)-3(x-6)=4(x-2)

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Solution for 2x+3(x-3)-3(x-6)=4(x-2) equation: 



2x+3(x-3)-3(x-6)=4(x-2)

We move all terms to the left:

2x+3(x-3)-3(x-6)-(4(x-2))=0

We multiply parentheses

2x+3x-3x-(4(x-2))-9+18=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

2x-(4x-8)+9=0

We get rid of parentheses

2x-4x+8+9=0

We add all the numbers together, and all the variables

-2x+17=0

We move all terms containing x to the left, all other terms to the right

-2x=-17

x=-17/-2

x=8+1/2

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