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2x+3(x-4)=2(2x-6)
We move all terms to the left:
2x+3(x-4)-(2(2x-6))=0
We multiply parentheses
2x+3x-(2(2x-6))-12=0
We calculate terms in parentheses: -(2(2x-6)), so:We add all the numbers together, and all the variables
2(2x-6)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
5x-(4x-12)-12=0
We get rid of parentheses
5x-4x+12-12=0
We add all the numbers together, and all the variables
x=0
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