2x+3(x-4)=2(2x-6)+x

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Solution for 2x+3(x-4)=2(2x-6)+x equation:


Simplifying
2x + 3(x + -4) = 2(2x + -6) + x

Reorder the terms:
2x + 3(-4 + x) = 2(2x + -6) + x
2x + (-4 * 3 + x * 3) = 2(2x + -6) + x
2x + (-12 + 3x) = 2(2x + -6) + x

Reorder the terms:
-12 + 2x + 3x = 2(2x + -6) + x

Combine like terms: 2x + 3x = 5x
-12 + 5x = 2(2x + -6) + x

Reorder the terms:
-12 + 5x = 2(-6 + 2x) + x
-12 + 5x = (-6 * 2 + 2x * 2) + x
-12 + 5x = (-12 + 4x) + x

Combine like terms: 4x + x = 5x
-12 + 5x = -12 + 5x

Add '12' to each side of the equation.
-12 + 12 + 5x = -12 + 12 + 5x

Combine like terms: -12 + 12 = 0
0 + 5x = -12 + 12 + 5x
5x = -12 + 12 + 5x

Combine like terms: -12 + 12 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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